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I'll start. |∫₀²π (sin3x/6)dx| + (log₃729)! / [∑ₖ=1⁴(k+3) + √169 - 5^(3/2)·5^(-1/2)]
Your turn.

Quoting MAK:

I'll start. \(\boxed{ \left| \int_{0}^{2\pi}\frac{\sin 3x}{6}\,\mathrm{d}x \right| + \frac{\big(\log_3 729\big)!}{\displaystyle \sum_{k=1}^{4}(k+3) \;+\; \sqrt{169} \;-\; 5^{\frac{3}{2}}\cdot 5^{-\frac12}} }\) Your turn.

hey, that's not a valid equation

Quoting 太空修补者:

hey, that's not a valid equation

It works. I just can't send photos, otherwise it would be much easier to understand.

Quoting MAK:

It works. I just can't send photos, otherwise it would be much easier to understand.

displaystyle is a HTML thing, not a math thing

Quoting MAK:

I'll start. |∫₀²π (sin3x/6)dx| + (log₃729)! / [∑ₖ=1⁴(k+3) + √169 - 5^(3/2)·5^(-1/2) Your turn.

also i've gone through it and ∑ₖ is missing 2 values, the rest of the equation is (if i've done this right which is unlikely since this is my first time with calculus)

720.1355173/(∑ₖ(k+11))

which assuming the intial value is 0 and the final value is 2, would be ~20, according to my calculator
assuming the intial value is 0 and the final value is 3 would be ~14
and assuming the intial value is 1 and the final value is 2 would be ~28

res = 3 * (4**2 - 10) + (81**0.5)/3 - 2**3 + (5*2 - 9)
print(res)


Quoting MrBird:

res = 3 * (4**2 - 10) + (81**0.5)/3 - 2**3 + (5*2 - 9)
print(res)


Google AI didn't let me copy the equation so I had to press the copy code thing.